In a family there are five children namely A, B, C, D and E. Each of them was born at the interval of 5 years. Now the sum of their ages is 75. Find the age of the youngest child.
Answers
Answered by
1
Answer:
Let
Age of A = a
Age of B = a + 5
Age of C = a + 5 + 5 = a + 10
Age of D = a + 5 + 5 + 5 = a + 15
Age of E = a + 5 + 5 + 5 + 5 = a + 20
a + a + 5 + a + 10 + a + 15 + a + 20 = 75
Grouping like terms
(a + a + a + a + a) + (5 + 10 + 15 + 20) = 75
5a + 50 = 75
5a = 75 - 50
5a = 25
a = 25/5
a = 5
Age of youngest child = 5 years
Answered by
1
Answer:
Let the age of E be 'x'
Then,
Age of D= x+5
Age of C= x+5+5= x+10
Age of B= x+5+5+5= x+15
Age of A= x+5+5+5+5= x+20
Sum of their ages= 75
Therefore,
x+x+5+x+10+x+15+x+20=75
5x+50=75
5x=75-50
x=25/5
x=5
Age of the youngest child= 5 years old.
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