in a family there are three children. assuming that the chances of a child being a male or female are equal.find the probability that there is at least one male child in the family.
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Pr(3 Boys|know about one boy by happenstance) = (1/8)/[1/8 + 3X/8 + 3*(1-X)/8]= (1/8)/[1/8 + 3/8] = 1/4.
rudeawakening:
will u pl tell again because u have written everything in too complicated way
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let x be the probability being a male child.
The possible outcomes are GGG, BGG, BBG, BBB = 4.
Then the probability of at least one boy is 3/4
The possible outcomes are GGG, BGG, BBG, BBB = 4.
Then the probability of at least one boy is 3/4
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