In a family there are three sisters named Shivani, Rekha and Vrinda. Pocket money has to be decided for them according to their ages. The eldest will get maximum and youngest will get minimum. The following information is given about their ages . Shivani is twice as old as Rekha and Vrinda is 9 years older than Rekha. Three years ago, Shivani was nine less than three times Rekha’s present age. Who will get the maximum pocket money and who will get the minimum?
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Rekha will maximum
Shivani will get minimum
Shivani will get minimum
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Let rekha’s present age be x
So, shivani’s present age= 2x
And vrinda’s present age= x+9
Now, 3 years ago,
Rekha’s age= x-3
Shivani’s age= 2x-3
And vrinda’s age= x+9
Now, according to the question
2x-3= 3(x-3)-9
➡️ 2x-3= 3x-9-9
➡️ 2x-3= 3x-18
➡️ -3+18= 3x-2x
➡️ 15= x
So, let’s see their present ages
Rekha’s age= x= 15 years
Shivani’s age= 2x= 30 years
And vrinda’s age= x+9= 24 years
So, shivani will get maximum
And rekha will get minimum
So, shivani’s present age= 2x
And vrinda’s present age= x+9
Now, 3 years ago,
Rekha’s age= x-3
Shivani’s age= 2x-3
And vrinda’s age= x+9
Now, according to the question
2x-3= 3(x-3)-9
➡️ 2x-3= 3x-9-9
➡️ 2x-3= 3x-18
➡️ -3+18= 3x-2x
➡️ 15= x
So, let’s see their present ages
Rekha’s age= x= 15 years
Shivani’s age= 2x= 30 years
And vrinda’s age= x+9= 24 years
So, shivani will get maximum
And rekha will get minimum
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