Question

In a family there are three sisters named Shivani, Rekha and Vrinda. Pocket money has to be
decided for them according to their ages as Rs. 100 X Age. The following information is given about
their ages.
Shivani is twice as old as Rekha and Vrinda is 9 years older than Rekha. Three years ago, Shivani
was mine vears less than three times Rekha's present age. Using linear equation find their pocket
money​

Answer 1

Let rekha’s present age be x

So, shivani’s present age= 2x

And vrinda’s present age= x+9

Now, 3 years ago,

Rekha’s age= x-3

Shivani’s age= 2x-3

And vrinda’s age= x+9

Now, according to the question

2x-3= 3(x-3)-9

➡️ 2x-3= 3x-9-9

➡️ 2x-3= 3x-18

➡️ -3+18= 3x-2x

➡️ 15= x

So, let’s see their present ages

Rekha’s age= x= 15 years

Shivani’s age= 2x= 30 years

And vrinda’s age= x+9= 24 years

So, shivani will get maximum

And rekha will get minimum

Answer 2

Answer: Rekha= 6 x100 =Rs600

Shivani=2x6=12x100 =Rs1200  

Vrinda =6+9=15x100 =Rs1500

Step-by-step explanation:

Let Rekha’s present age be x       3yrs ago  x-3

So, Shivani’s present age= 2x        3yrs ago   2x-3

And Vrinda’s present age= x+9      3yrs ago     (x+9)-3

from the question 2x-3 =3x -9  

2x-3x =-9+3  

-x=-6

x=6yrs

Rekha= 6yrs

Shivani=2x6=12yrs

Vrinda =6+9=15yrs

Rekha= 6yrs x100 =Rs600

Shivani=2x6=12yrs x100 =Rs1200  

Vrinda =6+9=15yrsx100 =Rs1500