Question

In a family two parents are carrier for albinism and
both have blood group 'AB'. What will be probability
of normal and type A blood group children
(1) 3/16
(2)6 /16
(3)2/16
(4)1/16​

Answer 1

Answer:

2/,16 is the probability I think

Answer 2

The probability of normal and type A blood group children is 3/16.

• Let, allele C represents the normal/dominant/wild type allele for albinism
• cc represents the recessive character that is albinism
• According to the question, parents are carrier so they are Cc,Cc.
• The cross is between,

         CcAB X CcAB

• Here AB represent the blood group
• The probability of normal child is 3/4 (CC=1/4, Cc= 2/4, cc= 1/4)
• The probability of having blood group A is 1/4 (AA=1/4, AB=2/4, BB=1/4)
• So, The probability of normal child is 3/4 * 1/4 =3/16