In a farm, there are 20 animals and their food provision lasts for 8 days. After 2 days, 10 more animals join the farm. For how many days will provision last now?
The question is from Direct and Inverse Variation lesson class 8.
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Let the food will now last for x days. Then,
Number of animals 20 30
Number of days 6 x
Clearly, more is the number of animals, less will be the number of days for food to last.
So, it is a case inverse proportion.
∴ 20 × 6 = 30x ⇒ x = 20×6/30 = 4
Hence, the food will now last for 4 days.
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