Math, asked by krishnaveni66775, 9 months ago

In a Farm there are 20 animals .buffalo gives 4 liters of milk. cow gives half liter of milk.goat quater liters of milk. per day they give 20 liters of milk. how many animals are there? buffalos? cows? goats? ​

Answers

Answered by sreesrh2008
2

Answer:

Assume number of respective animals are x,y,z.

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)Since buffalo gives 4litre and total milk is 20, x < 5

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)Since buffalo gives 4litre and total milk is 20, x < 5But from eq 3, x cannot be more than 4;

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)Since buffalo gives 4litre and total milk is 20, x < 5But from eq 3, x cannot be more than 4;Further if x=1 or 2; y>20... Not possible, since total animal is 20

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)Since buffalo gives 4litre and total milk is 20, x < 5But from eq 3, x cannot be more than 4;Further if x=1 or 2; y>20... Not possible, since total animal is 20Thus, x=3, y=15, z=2

Assume number of respective animals are x,y,z.x+y+z=20---(1) as the total number of animal has to be 20Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)Solving equation 1 and 2 we get15x+y=60 ----(3)Since buffalo gives 4litre and total milk is 20, x < 5But from eq 3, x cannot be more than 4;Further if x=1 or 2; y>20... Not possible, since total animal is 20Thus, x=3, y=15, z=2Ans: 3 buffalos, 15cows, 2goats.

Hope it helps, If so please matk as brainlest. And give votes.

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