in a farm there are some buffaloes and man if total no. of head 20 and total no. of legs are 64. find the no. of man and buffaloes.
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let the no. of man be X, then the no. of buffalo be (20-x) A/Q , 2x + 4(20-x) = 64 =2x +80-4x = 64 -2x =-16 or, X =16 therefore no.of man is 8 and no.of buffalo is and buffalo is 20-8 that is 12
aryan846851:
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