In a feequency distribution,the mid value of a class is 135 and the width of a class is 10.Find the upper limit of class
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Mid value =135 L1 =LOWER LIMIT
(L1 +L2) /2=135 L2 =UPPER LIMIT
L1 +L2 =270
L2-L1 =10 (given)
L2 +L1 =270 (EQUATION 1)
L2-L1=10 (EQUATION 2)
2L2 =280 (ON ADDING EQUATION 1 AND 2)
L2 =140
SO UPPER LIMIT IS 140
(L1 +L2) /2=135 L2 =UPPER LIMIT
L1 +L2 =270
L2-L1 =10 (given)
L2 +L1 =270 (EQUATION 1)
L2-L1=10 (EQUATION 2)
2L2 =280 (ON ADDING EQUATION 1 AND 2)
L2 =140
SO UPPER LIMIT IS 140
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