Math, asked by roshnilalwani48, 1 month ago

In a field, dry fodder for the cattle is heaped in a conical shape. The
height of the cone is 1.4 m. and the radius of base is 3.6 m. If it
is to be covered by a waterproof cloth in rainy season then how
much minimum cloth is needed?
[( π = 22 ) (√3=1.732) √17.37= 4.17]
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7

Answers

Answered by kumariniranjana79
0

Answer:

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Answered by ratnabegumkhan
1

Answer:

Height of the conical heap of fodder, h=2.1 m

Radius of the conical heap of fodder, r=

2

7.2

=3.6 m

∴ Volume of the fodder =

3

1

πr

2

h=

3

1

×

7

22

×(3.6)

2

×2.1=28.51m

3

(Approx)

Let the slant height of the conical heap of fodder be I m

∴I

2

=r

2

+h

2

⇒I

2

=(2.1)

2

+(3.6)

2

⇒I

2

=4.41+12.96=17.37

⇒I=

17.37

=4.17 m

Cover of the fodder =πrl=

7

22

×3.6×4.17=47.18m

2

∴ Minimum area of the polythin needed to cover the fodder in rainy season is 47.18 m

2

Step-by-step explanation:

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