Question

In a figure ab=ad, bc=cd,angle bad =100 and angle dbc=60 find the measures of angle adc and angle bcd​

Answer 1

Answer:

180=bcd+bdc+cdb,

180=60+60+bcd,(for bc=cd, assume bcd is isosceles ),

So, 180-120=bcd,

=>bcd=60.<=ans

bad is an isosceles triangle,for[ab=ad] so:

180=bad+abd+adb;

[since isosceles abd=adb, let them be x]

180=100+(2x) ;

180-100=2x;

x=40=adb;

So, adc=adb+bcd=100.<=ans