Question

in a figure; AB=DB and AC=DC. if angle ABD=58 degrees, angle DBC=(2x-4)degrees,angle ACB =y+15 degrees and angle DCB= 63 degrees;find the value of x and y.

Answer 1

Answer:

Step-by-step explanation:

AB=BD             ...(Given)

AC=CD              ...(Given)

AC=AC               ...(Common)

Thus, △ABC≅△DBC                 ...(SSS rule)

Hence, ∠DBC=∠ABC         ...(By CPCT)

∠DBC= $\frac{1}{2}$

2x−4=29

x=16.5 degree

Also, ∠ACB=∠DCB      ...(By cpct)

y+15=63

y=48 degree