in a figure AB parallel to CD, EF perpendicular to CD, angle GFC is 130, find x,y,z
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Given: AB//CD , EF perpendicular to CD
angleGFC = 130
To Find: x,y,z
since,
AB//CD and GF is a transversal
therefore,
x=130
x+y=180
130+y=180
y=50
now,
z = angleGFC - angle EFD
z=130-90
z=40
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