Question

in a figure ABCD is a parallelogram in which ab = 20 CM BC equal to 17 cm if De is parallel to a b and area of a parallelogram is 300 CM square find AE​

Answer 1

\boxed{\huge{\red{Answer}}}Answer

\underline{\huge{\blue{Given}}}Given

Area of parallelogram = 300 cm²

AB = 20 cm

BC = AD = 17 cm

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Area of parallelogram = b × h

\begin{gathered}300 \: {cm}^{2} = 20 \: cm \times h \\ h = \frac{300 \: {cm}^{2}}{20 \: cm} \\ h = 15 \: cm\end{gathered}300cm2=20cm×hh=20cm300cm2h=15cm

So, height of parallelogram = 15 cm

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In ∆ AED,

AD\longrightarrow⟶ 20cm

ED\longrightarrow⟶ 15cm

\begin{gathered}AE = \sqrt{{AD}^{2} - {ED}^{2} } \\ AE = \sqrt{400 - 225} \\ AE = \sqrt{175} \\ AE = 5

Answer 2

Step-by-step explanation:

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