In a figure, ABCD is a quadrilateral , in which AC and BD are the daigonals. If angle DBC=55' and angle BAC=45',find angle BCD
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BCD = 90 is your answer of questions
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Answer:
∆BCD=80°
Step-by-step explanation:
Given ;
∆ABCD is acyclic quadrilateral.
∆DBC = 55°
∆BAC = 45°
The angle inscribed in the same are is equal.
∆DBC = ∆DAC
∆DAC = 55°
Now,
∆DAB = ∆DAC + ∆CAB
∆DAB = 55° + 45° = 100°
∆DAB = 100°
The sum of opposite angles of cyclic quadrilateral is 180°.
∆BCD + ∆DAB = 180°
∆BCD + 100° = 180°
∆BCD = 80°
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