Math, asked by kahlonvarinder6096, 11 months ago

In a figure, ABCD is a quadrilateral , in which AC and BD are the daigonals. If angle DBC=55' and angle BAC=45',find angle BCD

Answers

Answered by ashutosh1920
0

BCD = 90 is your answer of questions


lovely9650256: are you a teacher
Answered by devpatel2356
1

Answer:

∆BCD=80°

Step-by-step explanation:

Given ;

∆ABCD is acyclic quadrilateral.

∆DBC = 55°

∆BAC = 45°

The angle inscribed in the same are is equal.

∆DBC = ∆DAC

∆DAC = 55°

Now,

∆DAB = ∆DAC + ∆CAB

∆DAB = 55° + 45° = 100°

∆DAB = 100°

The sum of opposite angles of cyclic quadrilateral is 180°.

∆BCD + ∆DAB = 180°

∆BCD + 100° = 180°

∆BCD = 80°

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