Question

in a figure ABCD is a rectangle. Prove that the sides of triangle ABC are equal to the sides of triangle ACD.​

Answer 1

Answer:

area of tringle =$\frac{1}{2}*BC*AB$

area of tringle =$\frac{1}{2}*6*2$ = 6 $cm^{2}$

area of tringle =$\frac{1}{2}*AD*DC$

area of tringle =$\frac{1}{2}*6*2$ = 6 $cm^{2}$

AREA OF TRINGLE ABC = AREA OF TRINGLE ADC

Step-by-step explanation: