Question

in a figure abcd is a trapezium ad=bc and be parallel ad ,whats the valuenof angle abd​

Answer 1

Step-by-step explanation:

Given, AD∥EF∥BC,

hence, ∠z=∠DAC=∠ACB (Alternate angles)

Thus, x=z=50

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Now, ∠ADF+∠EFD=180 (Angles between parallel lines)

y+120=180

y=60

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