in a figure ABCD is rhimbus in which bc =25cmand ao=24cm. find the sum of the lengths of diagonals
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Answer:
- THE SUM OF THE LENGTH OF THE DIAGONAL OF A RHOMBUS IS 62cm.
Step-by-step explanation:
Diagonals of a Rhombus is perpendicular to each other.
In triangle AOB we have:-
AO = 24cm
AB = 25cm
So by Phythagoras Theorem we have...
BO= √[(25)²-(24)²]
= 7cm
Also the Diagonals of a Rhombus bisect each other.
So, AC = 2AO = 2×24 = 48cm
BD = 2BO = 2×7 = 14cm
Thus, Sum of the length of Diagonals = 48+14
= 62cm
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Answer:
THE SUM OF THE LENGTH OF THE DIAGONAL OF A RHOMBUS IS 62cm.
Step-by-step explanation:
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