in a figure angle b a d = 3 Idiots angle DBA find angle CCD B and angle DBC and angle abc
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/_ADB= /_DBC + /_DCB(exterior angle property)
104=/_DBC + 65
104-65=/_DBC
39=/_DBC
/_CDB+ 39 +65=180(a.s.p.)
/_CDB+104=180
/_CDB = 180-104
=76
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