Question

in a figure angle poq is equal to 30 degree and radius op is equal to 12 cm find the area of the sector of prq and area of triangle o p q used by 3.14​

Answer 1

Step-by-step explanation:

Radius OP=OQ=r=12 CM

θ=30

and PM is perpendicular to OQ

Area of a sector of a circle OPQR =πr

2

(

360

θ

)

=3.14×(12)

2

×(

360

30

)

=37.68 cm

2

Area of △OQP=

2

1

×OQ×PM

=

2

1

×12×OP×sin30

=

2

1

×12×12×

2

1

=36 cm

2

Area of segment PRQ = (Area of a sector of a circle OPQR) - (Area of △OQP)

=(37.68−36)cm

2

=1.68 cm

2