In a figure angles (BAD=ADC)are right angle AE=BC if AB=BC=5cm and AD=9cm. find AD
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DC=9cm
Let me to explain it.
Draw a line joining BD
NOW CONGURENT TRIANGES,
ABC AND ACD
ANGLE BCD =BCA(90)
AB=BC (GIVEN)
BC=BC(COMMON)
TRIANGES ARE CONGURENT BY RHS
BY CPCT AD=DC
AD=9CM GIVEN
THEREFORE DC=9CM
IF YOU FOUND MY ANSWER HELPFUL THEN PLEASE MARK IT AS BRAINLIEST
Let me to explain it.
Draw a line joining BD
NOW CONGURENT TRIANGES,
ABC AND ACD
ANGLE BCD =BCA(90)
AB=BC (GIVEN)
BC=BC(COMMON)
TRIANGES ARE CONGURENT BY RHS
BY CPCT AD=DC
AD=9CM GIVEN
THEREFORE DC=9CM
IF YOU FOUND MY ANSWER HELPFUL THEN PLEASE MARK IT AS BRAINLIEST
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