Question

in a figure , how much is the sum of angle A+B+C+D​

Answer 1

Answer:

Step-by-step explanation:

Thus the top triangle has angles a, b + d, and c + e: Since the sum of the angles in a triangle is 180 degrees, and this triangle has the sum of all the corner angles, we are done! There are many other ways to prove the result too!

Answer 2

Step-by-step explanation:

Given : AB//CD

In ∆CED

x = 100°( vertically opposite angle)

25°+x+y = 180°

25°+100°+y = 180°

125°+y = 180°

y = 180°-125°

y = 55°

In ∆ABE

<y and < z is alternate angle so

<z = 55° bcoz (y is 55°)

25°and < P is alternate angle.

< P = 25°

< x = 100° in both triangle ( ∆ CED and ∆ ABE)

Hence , A= 55°

B = 25°

C = 25°

D = 55°

The sum of your given fig. is 360°(180°+180°)

Hope it helps u.