Question

in a figure if AB||BC and CD||EF then find value of x

Answer 1

Hey mate here is your answer ⤵⤵⤵

First of all AB is not parallel to BC .I Think AB||CF.

So,Now $\sf\angle BCF=\angle ABC=40°\sf(Alternate \\ \sf angles) \\ \\ \sf Now,\angle FCD=180°-\angle BCF+\angle ACB \\ \\ \sf \implies \angle FCD=180°-105°=75°\\ \\ \sf\implies \angle FCD=x=75°(Corresponding \sf \\\:\sf angles)$

❤hope it helps you ❤