Question

In a figure if QT ⊥ PR , ∠TQR = 40° , ∠SPR = 30° , FIND x and y?

Answer 1

Given :-

➔ QT ⊥ PR

➔ ∠TQR = 40°

➔ ∠SPR = 30°

To find :-

➔ Value of x and y

➔ Go through the attachment for the figure

Solution :-

➔ In ΔTQR :-

→ 90° + 40° + x° = 180°    (Angle Sum Property)

→ 130° + x° = 180°

→ x° = 180° - 130°

→ x° = 50°

➔ Now, In ΔPQR and line segment QR :-

→ y° = ∠SPR + x°    (Exterior angle Property)

→ y° = 30° + 50°

→ y° = 80°

➪ Values of x and y are 50° and 80°

Answer 2

Step-by-step explanation:

In ∆TQR , 90° + 40° + x = 180° ( Angle sum property of a traingle )

Therefore ,

x = 50°

Now ,

y = ∆SPR + x

Therefore ,

y = 30° + 50°

= 80°