In a figure M is the mid point of side CD of a parallelogram ABCD . the line BM is drawn intersecting AC at L and AD at E. Prove that EL= 2BL
Answers
Answered by
33
Answer:
ΔBCM & ΔEDM are similar.
MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar.
EL / BL = AE / BC = 2
So EL = 2 BL
Attachments:
Answered by
31
Answer:
EL = EM + LM
EL = BM + BL/2
EL = BL + LM + BL/2
EL = BL + BL/2 + BL/2
EL = BL + BL
EL = 2BL
proved.
Attachments:
Similar questions