in a figure p is the midpoint of a b and d is the midpoint of AC prove that ad is equal to one fourth of CD
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Question:
I guess this is your question: If AB is a line and C is the mid-point of AB and D is mid-point of AC then prove that AD=¼AB
Solution:
AC = CB (as C is the mid-point of line segment AB)
Add AC to both sides, we get
AC + AC = AC + CB ( If equals are added to equals, then the wholes are equal)
So, 2 AC = AB (as AC+CB = AB)
AC = AB/2 ........ (1)
Next, AD = DC (as D is the mid-point of AC)
Add AD to both sides, we get
AD + AD = AD + DC (If equals are added to equals, the wholes are equal)
2 AD = AC (as AD + DC = AC)
Therefore, AD = AC÷2 ......... (2)
Substituting value of AC from (1) in (2), we get
AD = AB/2÷ 2
AD = AB/2 x ½
AD = ¼AB
Thus, proven
Hope you've understood!
Please mark as the brainliest!
vineeth12375:
Thanks a lot guy
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