Question

In a figure , ST||RQ PS=3cm and SR=4cm. Find the ratio of the area of triangle PST to the area of triangle PRQ

Answer 1

ST//RQ
PS=3CM
SR=4CM
we know that the ratio of area of two similar triangle is equal to the ratio of square of their corresponding side
ar (angle PST)/ar (angle PRQ)=(PS)^/(PR)^
=(3)^/(PS/SR )^
=9/(3+4)^
=9/(7)^
=9/49
hence the required ratio is 9:49

Answer 2

Answer:

9:49

Step-by-step explanation:

Given

ST || RQ

PS= 3 cm

SR = 4cm

Proof :--

ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49