In a figure straight lines AB and CD intersect at P; and AC//BD...
prove:
Triangle APC and Triangle BPD are similar
If BD=2.4, AC=3.6, PD=4.0cm and PB=3.2; find lengths of PA and PC
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10
Answer:
AP=4.8
PC=6
angle apc= angle bpd
since AC//BD
ANGLE ACP= BDP
HENCE TRIANGLE APC BPD ARE SIMILAR
ayesha469:
can u pls explain
Answered by
18
Answer:
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