In a figure, the tent is in the shape of cylinder surmounted by conical top of same diameter. If height and diameter of cylindercal part are 2.1 m and 3m respectively and the slant height of conical part is 2.8m. Find the area.
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Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
=πrl+2πrh
=π×2×2.8+2π×2×2.1
=2π[2.8+4.2]
=2×22/2×7
=44m²
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