In a figure,triangle ABC is an isosceles triangle in which AB=AC. If E and F be the midpoints of AC and AB respectively ,prove that BE=CF.
please give the solution now is urgent
Answers
Answered by
14
see, AB = AC
and E is the mid point on AB,
⇒ AE = BE
⇒AB = AE + BE
=AE + AE = 2AE
⇒AB = 2AE
and F is the mid point of AC
⇒AF = CF
AC= AF + CF
=CF + CF
=2CF
AC= 2 CF
∵ AB = AC
∴ 2 AE = 2 CF
⇒ AE = CF (proved )
and E is the mid point on AB,
⇒ AE = BE
⇒AB = AE + BE
=AE + AE = 2AE
⇒AB = 2AE
and F is the mid point of AC
⇒AF = CF
AC= AF + CF
=CF + CF
=2CF
AC= 2 CF
∵ AB = AC
∴ 2 AE = 2 CF
⇒ AE = CF (proved )
ravishashoo:
ple explainin detail
Answered by
35
In triangle BFC and EBC,
BF=CE
Angle B = Angle C
BC=BC
Triangle BFC is congruent to Triangle ECB by SAS test
Therefore, BE=CF (By cpct)
BF=CE
Angle B = Angle C
BC=BC
Triangle BFC is congruent to Triangle ECB by SAS test
Therefore, BE=CF (By cpct)
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