in a fiq S and T are the mid point of PR and PQ of Triangle PQR ,Area of Triangle PQR =48cm then find area of triangle TSQ
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∆PTS is half of ∆PQR
therefore ar(∆PTS)=1/2*48=24
ar(QRST)=24
ar(∆QTS) is half of ar(QRST)
therefore ar(∆QTS) = 1/2*24
= 12 cm²
arunkumar33:
oh
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ans is 12 cm2...........
.
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