Question

in a first order reaction 30% decomposition takes place in 40 minutes calculate Half Life​

Answer 1

Answer:

77.7 min approximately

Explanation:

For a first order reaction,

t = 2.303/k Log [R]º / [R]

k = 2.303/40min Log 100 / 100-30

= 2.303/40min Log 10 / 7

= 8.918 x 10-3 min-1

Therefore, t1/2 of the decomposition reaction is

t1/2 = 0.693/k

= 0.693 / 8.918 x 10-3 min

= 77.7 min (approximately)