Chemistry, asked by kerbaghatage9, 20 days ago

In a first order reaction 60%of the reactant decompose in 45 minutes calculate the half life of the reaction

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Answered by shekhawatpayal320
0

Answer:

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>>In a first order reaction A → B, 60% of

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In a first order reaction A→B,60% of the given sample of compounds decomposes in 45 minutes. The half life of the reaction is ______________.

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Correct option is B)

For the first order reaction,

k=

t

2.303

a−x

Log a

where,

k=rate constant

t=age of sample

a=let initial amount of the reactant

a−x=amount left after decay process

k=

45

2.303

100−60

Log 100

k=

45

2.303

log

2

5

k=0.02 min

−1

-------------------------------(1)

t

1/2

=

k

0.693

------------------------------------(2)

on putting value of k in equation (2) from (1) we will get:

t

1/2

=

0.02

0.693

=34.65

Explanation:

i hope it's helpful

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