Question

In a first-order reaction A ➝ B, if k is rate
constant and inital concentration of the reactant
A is 0.5 M, then the half-life is
(a)log2/k (b) log2/k√0.5
(c) In2/kt (d) 0.693/0.5k

Answer 1

$\boxed{\huge{\red{\mathfrak{Answer}}}}$

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(c) ln2/kt

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$For\:a\:{1}^{st}\:order\:kinetics$

$k = \frac{2.303}{t}{log}_{10} \frac{a}{a - x} \\ \\ At \: \: {t}_{ \frac{1}{2} }, \\ \\ \: k = \frac{2.303}{t \frac{1}{2} } log_{10} \frac{a}{a - 2} \\ \\ or, \\ \\ t_{ \frac{1}{2} } = \frac{2.303}{k} log_{10}(2) = \frac{ln2}{k}$

Answer 2

Hello Friend..!!

The answer of ur question is..!!

Option.C

Thank u..!!