Question

In a first order reaction A ~product 60% of the given Sample of A decomposers in 40min.what is half life of the reaction?

Answer 1

Answer:

For the first order reaction,

T=2.303/K×log(a/a-x)

Here,T=40min

x=60

40=2.303/k×log(100/100-60)

40=2.303/k×log(100/40)

40=2.303/k×log(5/2)

k=2.303/40×0.40

k=2.303/100

k=0.023min^-1

The half life of the reaction is,

t1/2=0.693/K

t1/2=0.693/0.023min^-1

t1/2=30min

Explanation:

Hope it helps you....