Question

In a first order reaction for every 10° rise in temperature,
the rate is doubled. If the temperature of reaction is
increased from 20°C to 60°, the rate of reaction will
become
Eight times
Four times
Sixteen times
Two times​

Answer 1

Given:

The rate is doubled for every 10° rise in temperature.

Initial temperature = 20 °C

Final Temperature = 60 °C

To Find:

The rate of reaction after the rise in temperature.

Calculation:

- According to the given condition, the rate of reaction becomes 2ⁿ times where n is the integral multiple of 10.

- The rise in temperature, ΔT = 60 - 20 = 40 °C

- The value of n = 40/10 = 4

- So, the rate of reaction becomes = 2⁴ = 16

- So, the rate of reaction after the rise in temperature will be (c) Sixteen times.