Question

In a first order reaction t ½ = 1000 minutes calculate its rate constant

A. 6.93 x 10-3 min-1
B.6.93 x 10-4min-1
C.6.93 x 103
min-1
D.6.93 x 10 4
min-1​

Answer 1

Answer:

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Answer 2

Given : first order reaction t ½ = 1000 mins

Half time = 1000 mins

To Find : rate constant of first order reaction

Solution:

first order reaction

$A=A_0e^{-kt}$

=> t = (1/k) ln(A₀/A)

A₀ = initial

A = remaining

t = time

k =  rate constant  

t will be half time if  A = A₀/2

=> A₀/A = 2

Half time = 1000 mins

=> 1000 = (1/ k ) ln(2)

=> k = ln(2)/1000

=> k = 6.93 * 10⁻⁴  min⁻¹

 

Hence rate constant​  6.93 * 10⁻⁴  min⁻¹

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