Chemistry, asked by kaustubhparab, 1 year ago

In a first order reaction, the concentration of the
reactant decreases from 0.6 M to 0.3 M in 15
minutes. The time taken for the concentration to
change from 0.20 M to 0.05 M in minutes is​

Answers

Answered by AneesKakar
1

Answer:

For the given equation we know that at time t= 0 concentration was 0.6 and at t= 15min tye concentration was 0.3.

Thus, the equilibrium constant will be same since the half life of 0.20 will be 0.10 and again its half life will be 0.05 thus the time required will be 2*half life which is 2*15 = 30 minutes will be required to complete the reaction from 0.2 to 0.05.

Similar questions