Question

In a first order reaction the concentration of the reactant decreases from 0.8M to 0.4 M in 15 min the time taken for the concentration to change from 0.1M to 0.025M is

Answer 1

For decreasing 0.4m is takes 15min.So for decreasing of per 0.1M it takes 15/4=3.75min.So to decrease from 0.1M to 0.025M that is 0.75M it will take one from four part of 3.75min ie: 3.75/4=0.9375mins

Answer 2

Answer : 30 Minutes

The time taken  for the concentration to change from 0.1 M to 0.025 M is  30 Minutes

Explanation :

Hey Mate,

I will give you the simplest method of solving those types of questions in a few seconds. So, lets solve this.

Given : Concentration of the reactant, Decreases from 0.8M to 0.4M in 15 Minutes.

Means, The Concentration of reactant get half in 15 minutes. (From 0.8 to 0.4M)

So, t₁₎₂ = t (half) = 15 Minutes

Then,

In 15 minutes, Concentration of the reactant, Decreases from 0.1M to 0.05M and in another 15 minutes it's decreases from 0.05M to 0.025M.

So,

The total time taken  for the concentration to change from 0.1 M to 0.025 M is  30 Minutes.

Take a Look :

Find the change in velocity of the car in the time interval between t_1 = 1.00 s and t_2 = 3.00 s.

https://brainly.in/question/15314395

A metal sphere of radius 0.1m is charged to a potential 36kv and kept at the corner B ......

brainly.in/question/7646454