In a first order reaction the concentration of the reactant decreases from 0.8M to 0.4 M in 15 min the time taken for the concentration to change from 0.1M to 0.025M is
Answers
For decreasing 0.4m is takes 15min.So for decreasing of per 0.1M it takes 15/4=3.75min.So to decrease from 0.1M to 0.025M that is 0.75M it will take one from four part of 3.75min ie: 3.75/4=0.9375mins
Answer : 30 Minutes
The time taken for the concentration to change from 0.1 M to 0.025 M is 30 Minutes
Explanation :
Hey Mate,
I will give you the simplest method of solving those types of questions in a few seconds. So, lets solve this.
Given : Concentration of the reactant, Decreases from 0.8M to 0.4M in 15 Minutes.
Means, The Concentration of reactant get half in 15 minutes. (From 0.8 to 0.4M)
So, t₁₎₂ = t (half) = 15 Minutes
Then,
In 15 minutes, Concentration of the reactant, Decreases from 0.1M to 0.05M and in another 15 minutes it's decreases from 0.05M to 0.025M.
So,
The total time taken for the concentration to change from 0.1 M to 0.025 M is 30 Minutes.
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