Question

In a first order reaction the concentration of the reactant is reduced to one fourth of its initial value is 50 seconds. Calculate the rate constant of the reaction

Answer 1

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Expression for rate law for first order kinetics is given by:

k= 2303/t log a/a-x

where,

k = rate constant  = ?

t = time taken = 50 seconds

a = let initial amount of the reactant  = a

a - x = amount left after decay process  = a/4

Now put all the given values in above equation, we get

k =2.303 / 50 log a/a/x

k = 2.303/50 log 4

k =0.028 / sec

Rate constant for the reaction

R = 0.028/ sec

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Answer 2

The specific rate constant (k) is the proportionality constant relating the rate of the reaction to the concentrations of reactants. The rate law and the specific rate constant for any chemical reaction must be determined experimentally. The value of the rate constant is temperature dependent.