In a fitness certificate, by mistake a candidate gave his height as 25% more than normal. In the interview panel, he clarified that his height was 5 feet 5 inches. Find the percentage correction made by the candidate from his stated height to his actual height.
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Answer:
20% correction
Step-by-step explanation:
height mentioned = H
Normal height = 5 ft 5inches = 5*12 +5 = 65 inches
H = 65 + (25/100)*65 = 65*1.25 = 81.25 inches
Height mentioned in interview = 65 inches
Correction made = 81.25 - 65 = 16.25 inches
% correction from stated height = (16.25/81.25)*100 = 20 %
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