Question

In a five digit number 24yx9,x is the greatest single digit perfect cube and exceeds twice of y by 2.the difference of the number and itd cube root is

Answer 1

Answer:

The digit is 29.

Step-by-step explanation:

x is greatest single digit perfect cube . So x is 8 which is only single digit perfect cube.

x=8..............(1 )

by data x exceeds twice of the y by 2..

Therefore

x=2y+2

8 = 2y + 2

y = 3.............(2 )

Now we have got both the values of x and y

Therefore the number is

24389

Now taking cube root of  24389.

3√24389  = 29

Thus the digit is 29.

Answer 2

24,360‬ is the difference of the number and its cube root  for 24yx9

Step-by-step explanation:

x is the greatest single digit perfect cube

Single Digit perfect cube are

1 & 8

8 > 1

=> x = 8

x = 2y + 2

=> 8 = 2y + 2

=> 2y = 6

=> y = 3

24389

∛24389 = 29

difference of the number and its cube root is

24389 - 29

= 24,360‬

Learn More :

The three digit number XYZ

https://brainly.in/question/12125666