Math, asked by vedanshniranjan678, 18 days ago

In a flat race, the runners up, running at 10/3 m/s lost by 3 secs to the winner. If the runners up took 15 secs to cover the distance, what was the speed of the winner?

Answers

Answered by RvChaudharY50
1

Given :- In a flat race, the runners up, running at 10/3 m/s lost by 3 secs to the winner. If the runners up took 15 secs to cover the distance, what was the speed of the winner ?

Solution :-

→ Speed of runner up = 10/3 m/s

→ Time taken by runner up = 15 seconds

so,

→ Distance covered by runner up = Length of race = speed * time = 10/3 * 15 = 50 m .

now since runner up lost by 3 seconds .

then,

→ Time taken by winner = 15 - 3 = 12 seconds

therefore,

→ Speed of winner = Length of race / time taken = 50/12 = (25/6) m/s (Ans.)

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