Question

In a flight, 20 percent of a passengers held round-trip tickets and also took their pets abroad the
flight. If 60 percent of the passengers with round-trip tickets did not take their pets abroad the
flight, what percent of the flight's passengers held round-trip tickets?
A. 33.33%
B. 40%
C. 50%
D. 66.67%
E. None of these.​

Answer 1

Answer:

60%-20%=40%

ans is 40%ok

you please give me your book ans

Answer 2

Answer:

50% ( C )

Step-by-step explanation:

Let the total of passengers be 100.

Now, 20 passengers held round-trip tickets and pets.

As 60% of the passengers with round-trip tickets did not take their pets then 40% of the passengers with round-trip tickets did take their pets, so of passengers with round-trip tickets and pet is 40% of the passengers with round-trip tickets.

If we take of the passengers with round trip tickets to be "X" then we'll have.

0.4 X = 20

X = 50