in a flight of 2800 km an air craft was slowed down due to bad weather. the avg speed is reduced by 100 km/hr and the time is increased by 30 mins . find the original duration of the plane. NO SPAMMING, PLEASE ANSWER ONLY IF YOU KNOW OR ELSE I WILL REPORT YOUR ANSWER !!!
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Let speed be x km/hr
time taken at normal speed = 2800/x hr
30 min = 30/60 hr = 1/2 hr
time taken after the speed was slowed down 2800/x - 100 hr
now, as per question,
2800/x-100 = 2800/x + 1/2
2800/x-100 - 2800/x = 1/2
(2800x - 2800x + 280000) / x2-100x = 1/2
280000 / x2-100x = 1/2
560000 = x2-100x
x2-100x-560000 = 0
x2-800x+700x-560000 = 0
x(x-800) + 700(x-800) = 0
(x+700) (x-800) = 0
so x = 800
so original duration of the flight = 2800/800 hr
= 3 hr 30 min
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