In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 kmph and time is increased by 30 minutes. Find the original duration of the flight.
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speed be x
distance= 2800 km
t = 2800/x
speed is reduced by 100
speed = x - 100
time = 2800 / ( x - 100 )
Its average speed is reduced by 100 kmph and time is increased by 30 minutes (1/2 h ).
(2800 / x - 100) - 2800/x = 1/2
x=-700 , x= 800
-700 will be neglected,speed is not negative
x = 800
time = 2800 / 800
time = 7/2 hours
distance= 2800 km
t = 2800/x
speed is reduced by 100
speed = x - 100
time = 2800 / ( x - 100 )
Its average speed is reduced by 100 kmph and time is increased by 30 minutes (1/2 h ).
(2800 / x - 100) - 2800/x = 1/2
x=-700 , x= 800
-700 will be neglected,speed is not negative
x = 800
time = 2800 / 800
time = 7/2 hours
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