In a flight of 2800km an aircraft was slowed down due to bad weather its average speed is reduced by 100km/h and time increased by 30 minutes . find the original duration. Of the flight
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Speed=distance/time
So, x=2800/t
Where x is speed and t is time.
Then, t = 2800/x
Now atq:-
X-100=2800/2800/x + 1/2
X-100 = 2800(2x)/5600+x
X^2-100x+5600x-560000=5600x
X^2-100×-560000=0
Therefore,x=950.
Then,t=2800/950
T=2.94h
I.e. t=176.4 minutes...
Hope its correct......
Mark it as brillient.....
PARTHIPAN6297:
Answer 3.30 hrs
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