In a flight of 600 km,an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr. Find the total journey in km.
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Let the duration of the flight be x hours.
Then, 600 - 600 = 200
x x + (1/2)
600 - 1200 = 200
x 2x + 1
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
NakkaRuchir150:
sww means
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4
The duration of the flight is 1 hour
Let the duration of the flight be x hours.
Then,600/x-600/x + (1/2)= 200
600/x-1200/2x + 1= 200
x(2x + 1) = 3
2x² + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr
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