Question

In a flight of 6000 km , an aircraft was slowed down due to bad weather. The average speed for the trip was reduced by 400km/h and the time of flight increased by 30 minute.Find the original duration of the flight.

Plz help me @YashtheINDIAN @lastbenchstudent @jishnumukherjee @riturajbabu

Answer 1

Sol: Let the original speed of the aircraft be 'x' km/hr Decreased speed of the aircraft = (x - 400) km/hr Time = Distance/Speed Original duration of the flight = (6000 / x) hrs Duration of the flight with decreased speed = (6000 / x-400) hrs Difference of time = 30 min = 1/2 hrs ⇒ (6000 / x-400) - (6000 / x) = 1/2 ⇒ (6000x - 6000x + 2400000) / x(x - 400) = 1/2 ⇒ x2 - 400x = 4800000 ⇒ x2 - 400x - 4800000 = 0 ⇒ (x - 2400)(x + 2000) = 0 ⇒ x = 2400 or -2000 Positive value of x is 2400. Therefore original speed of the aircraft is 2400 km/hr. Original duration of the aircraft = 6000/2400 = 2.5 hrs

Answer 2

so here is answer

2.5 hours