Question

In a flight of 6000km , an aircraft was slowed down due to bad weather. The average speed for the tips was reduced by 400km and the time of flight increase by 30 minutes. Find the original duration of the flight. Pzz help me solve this.

Answer 1

.... I hope you understand

Answer 2

Hiii friend,

LET THE ORIGINAL SPEED BE X Km / hr

THEN,

Reduced speed = (X-400) km/hr

The duration of flight at original speed = (6000/X) hour.

The duration of flight at reduced speed = (6000/X-400) hour.

The difference in two duration = (1/2) hour.

SINCE,

600/(X-400) - 6000/X = 1/2

= 1/(X-400) - 1/X = 1/12000

= X-(X-400)/X(X-400) = 1/12000

= 400/X(X-400) = 1/12000

= X(X-400) = 4800000 = 0

= X² - 400X - 4800000 = 0

= X²-2400X+2000X - 4800000 = 0

= X(X-2400) + 2000(X-2400) = 0

= (X-2400) ( X+2000) = 0

= X -2400 = 0. OR X+2000 = 0

= X = 2400. OR X = -2000

SINCE ,

SPEED CAN'T BE NEGATIVE.

SO ,

X = 2400 Km/hr

THEREFORE,

ORIGINAL SPEED = 2400 Km/hr


TIME = DISTANCE/SPEED

THEREFORE,

ORIGINAL DURATION OF THE FLIGHT = DISTANCE/ SPEED = (6000/2400) HOURS = 5/2 HOURS...


HOPE IT WILL HELP YOU ...... :-)